23x^2-80x-48=0

Solution for 23x^2-80x-48=0 equation:

23x^2-80x-48=0

a = 23; b = -80; c = -48;
Δ = b2-4ac
Δ = -802-4·23·(-48)
Δ = 10816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10816}=104$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-104}{2*23}=\frac{-24}{46}
=-12/23
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+104}{2*23}=\frac{184}{46}
=4
$